
设Y = f(x) = cosx , x属于Rf(-x) = cos(-x)= cosx = f(x)所以f(x)是偶函数设y = g(x)= xcosx , x属于Rg(-x) = -xcos(-x)= -xcosx = -g(x)所以g(x)是奇函数

设Y = f(x) = cosx , x属于Rf(-x) = cos(-x)= cosx = f(x)所以f(x)是偶函数设y = g(x)= xcosx , x属于Rg(-x) = -xcos(-x)= -xcosx = -g(x)所以g(x)是奇函数